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The square of the hypotenuse (c - the side opposite the right angle) is equal to the sum of the squares of the other two sides (a and b) of a right triangle.



Initial Data


$$ax^{2}+bx+c=0$$


a =

b =

c =


Result


$$x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$$


x1 =

x2 =