The square of the hypotenuse (c - the side opposite the right angle) is equal to the sum of the squares of the other two sides (a and b) of a right triangle.

## Initial Data

$$ax^{2}+bx+c=0$$

a =

b =

c =

## Result

$$x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$$

x1 =

x2 =